| Summary: | function assume previus value | ||
|---|---|---|---|
| Product: | [Applications] kalgebra | Reporter: | Diego Candido <kell.92.k> |
| Component: | general | Assignee: | Aleix Pol <aleixpol> |
| Status: | RESOLVED FIXED | ||
| Severity: | normal | ||
| Priority: | NOR | ||
| Version: | unspecified | ||
| Target Milestone: | --- | ||
| Platform: | Compiled Sources | ||
| OS: | Linux | ||
| Latest Commit: | Version Fixed In: | ||
| Sentry Crash Report: | |||
SVN commit 1206278 by apol: Forget about the older value of the variable before defining the new one. BUG: 258304 M +1 -0 analyzer.cpp WebSVN link: http://websvn.kde.org/?view=rev&revision=1206278 |
Version: unspecified (using KDE 4.5.1) OS: Linux Let's say we have the following function: f:=x->piecewise {x>10 ? f(x+1), ? x} if i'll rewrite it, it will be evaluated as: x->piecewise { x>10 ? (x->piecewise { x>10 ? f(x+1), ? x })(x+1), ? x } so f(x+1) will be evaluated and exchanged with his definition Reproducible: Always Actual Results: Function is exchanged with its previous definition Expected Results: Function must not be exchanged for its definition